Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 470: 136

Answer

$1+5i$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL method, the expression $ (3+2i)(1+i) $ simplifies to \begin{array}{l} 3(1)+3(i)+2i(1)+2i(i) \\= 3+3i+2i+2i^2 \\= 3+5i+2(-1) \\= 1+5i .\end{array}
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