Answer
$1+5i$
Work Step by Step
Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL method, the expression $
(3+2i)(1+i)
$ simplifies to
\begin{array}{l}
3(1)+3(i)+2i(1)+2i(i)
\\=
3+3i+2i+2i^2
\\=
3+5i+2(-1)
\\=
1+5i
.\end{array}
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