Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 470: 127

Answer

$2i\sqrt{2}$

Work Step by Step

Using $i=\sqrt{-1}$ and the properties of radicals, the expression $ \sqrt{-8} $ simplifies to \begin{array}{l} \sqrt{4\cdot2}\cdot\sqrt{-1} \\= 2i\sqrt{2} .\end{array}
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