## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 7 - Review - Page 470: 144

#### Answer

$-x^4y$

#### Work Step by Step

Using the properties of radicals, the expression $\sqrt[3]{-x^{12}y^3}$ simplifies to \begin{array}{l} \sqrt[3]{-(x^4)^3y^3} \\= -x^4y .\end{array}

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