Answer
$-5-12i$
Work Step by Step
Using $(a+b)^2=a^2+2ab+b^2$ , the expression $
(2-3i)^2
$ simplifies to
\begin{array}{l}
(2)^2+2(2)(-3i)+(-3i)^2
\\=
4-12i+9i^2
\\=
4-12i+9(-1)
\\=
-5-12i
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Review - Page 470: 137
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