Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 470: 147

Answer

$\dfrac{1}{8}$

Work Step by Step

Using $a^{m/n}=\sqrt[n]{a^m}$ and $a^{-1}=\dfrac{1}{a}$, the expression $ 64^{-1/2} $ simplifies to \begin{array}{l} \dfrac{1}{64^{1/2}} \\\\= \dfrac{1}{\sqrt{64}} \\\\= \dfrac{1}{8} .\end{array}
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