Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 470: 147



Work Step by Step

Using $a^{m/n}=\sqrt[n]{a^m}$ and $a^{-1}=\dfrac{1}{a}$, the expression $ 64^{-1/2} $ simplifies to \begin{array}{l} \dfrac{1}{64^{1/2}} \\\\= \dfrac{1}{\sqrt{64}} \\\\= \dfrac{1}{8} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.