Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 470: 123

Answer

$3\sqrt{2} \text{ cm}$

Work Step by Step

Using $a^2+b^2=c^2$ (or the Pythagorean Theorem) with legs having measures $3$ and $3$, then the hypotenuse, $c$, is \begin{array}{l}\require{cancel} 3^2+3^2=c^2 \\\\ 9+9=c^2 \\\\ 18=c^2 \\\\ c=\sqrt{18} \\\\ c=\sqrt{9\cdot2} \\\\ c=\sqrt{(3)^2\cdot2} \\\\ c=3\sqrt{2} .\end{array} Hence the hypotenuse is $ 3\sqrt{2} \text{ cm} .$
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