Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set - Page 323: 73


105 units

Work Step by Step

C(x)=x^2-15x+50 C(x)=9500 9500=x^2-15x+50 x^2-15x+50-9500 Simplify x^2-15x-9450 Using ac method a=9450 b=-15 Find two numbers whose products are 9450 and whose sums are -15. The two numbers are -105 and 90 so rewrite x^2-105x+90x-9450=0 x(x-105)+90(x-105) (x+90)(x-105)=0 x+90=0 x=-90 x-105=0 x=105 Since the answer can't be negative then production of 105 units would cost $9500. C(x)= (105)^2-15(105)+50 C(x)= 9500
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