Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set - Page 323: 16


$\frac{c^{2}}{20}$ - $\frac{c}{4}$ + $\frac{1}{5}$ = 0 c = 4 , 1

Work Step by Step

Directions: Solve each equation. $\frac{c^{2}}{20}$ - $\frac{c}{4}$ + $\frac{1}{5}$ = 0 $\frac{c^{2}}{20}$ - $\frac{5c}{20}$ + $\frac{4}{20}$ = $\frac{0}{20}$ Multiply each fraction to get a common denominator of 20 $c^{2}$-5c+4=0 All parts of equation are over 20, therefore, you can rewrite the equation without the denominator (c-4)(c-1)=0 Factor c=4,1 Find values that make new equation true. c-4=0 and c-1=0, so c=4 and 1.
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