Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set - Page 323: 17


$x=\left\{ \dfrac{2}{5},-\dfrac{1}{2} \right\}$

Work Step by Step

Multiplying both sides by the $LCD= 20 $, then the solution to the given equation, $ \dfrac{x^2}{2}+\dfrac{x}{20}=\dfrac{1}{10} $, is \begin{array}{} 10(x^2)+1(x)=2(1) \\\\ 10x^2+x=2 \\\\ 10x^2+x-2=0 \\\\ (5x-2)(2x+1)=0 .\end{array} Equating each factor to zero, then $ x=\left\{ \dfrac{2}{5},-\dfrac{1}{2} \right\} $.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.