#### Answer

$x=5$

#### Work Step by Step

The factored form of the given expression, $
\dfrac{x^2}{10}+\dfrac{5}{2}=x
$, is
\begin{array}{l}
10\left( \dfrac{x^2}{10}+\dfrac{5}{2} \right)=(x)10
\\\\
x^2+25=10x
\\\\
x^2-10x+25=0
\\\\
(x-5)(x-5)=0
\\\\
(x-5)^2=0
.\end{array}
Using the Square Root Property, then
\begin{array}{l}
x-5=\pm\sqrt{0}
\\
x-5=0
\\
x=0+5
\\
x=5
\end{array}