Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set - Page 323: 66



Work Step by Step

Using properties of equality, the solution to the given expression, $ 7c-2(3c+1)=5(4-2c) $, is \begin{array}{l} 7c-6c-2=20-10c \\\\ c+10c=20+2 \\\\ 11c=22 \\\\ c=\dfrac{22}{11} \\\\ c=2 .\end{array}
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