Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set - Page 323: 63



Work Step by Step

The solution to the given expression, $ x(x-3)=x^2+5x+7 $, is \begin{array}{l} x^2-3x-x^2-5x-7=0 \\\\ -8x-7=0 \\\\ -8x=0+7 \\\\ -8x=7 \\\\ x=\dfrac{7}{-8} \\\\ x=-\dfrac{7}{8} .\end{array}
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