Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set - Page 323: 61


$x=\left\{ -\dfrac{1}{3},0 \right\}$

Work Step by Step

The factored form of the given expression, $ 3x^2=-x $, is \begin{array}{l} 3x^2+x=0 \\\\ x(3x+1)=0 .\end{array} Equating each factor to zero, then \begin{array}{l} x=0 ,\text{ OR}\\\\ 3x+1=0 \\ 3x=0-1 \\ 3x=-1 \\ x=-\dfrac{1}{3} .\end{array} Hence, $ x=\left\{ -\dfrac{1}{3},0 \right\} $.
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