Intermediate Algebra (6th Edition)

$x=\left\{ \dfrac{1}{5},4 \right\}$
Multiplying both sides by the $LCD= 6$, then the solution to the given equation, $\dfrac{5x^2}{6}-\dfrac{7x}{2}+\dfrac{2}{3}=0$, is \begin{array}{} 1(5x^2)-3(7x)+2(2)=6(0) \\\\ 5x^2-21x+4=0 \\\\ (5x-1)(x-4)=0 .\end{array} Equating each factor to zero, then $x=\left\{ \dfrac{1}{5},4 \right\}$.