Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set - Page 323: 20


$x=\left\{ \dfrac{1}{5},4 \right\}$

Work Step by Step

Multiplying both sides by the $LCD= 6 $, then the solution to the given equation, $ \dfrac{5x^2}{6}-\dfrac{7x}{2}+\dfrac{2}{3}=0 $, is \begin{array}{} 1(5x^2)-3(7x)+2(2)=6(0) \\\\ 5x^2-21x+4=0 \\\\ (5x-1)(x-4)=0 .\end{array} Equating each factor to zero, then $ x=\left\{ \dfrac{1}{5},4 \right\} $.
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