## Intermediate Algebra (6th Edition)

$V(x)=x(x+4)(x-2)$
Factor out the GCF of $x$ to have: $\\V(x)=x(x^2+2x-8)$ $\\\\$The factors of $-8$ whose sum is equal to the middle term (2) are 4 and 2. Thus, the factored form of the trinomial is $(x+4)(x-2)$. Therefore, the completely factored form of the given expression is: $\\V(x)=x(x+4)(x-2)$