Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 304: 108

Answer

$(3x^n+4)^2$

Work Step by Step

RECALL: $a^2+2ab+b^2=(a+b)^2$ The given trinomial can be written as: $(3x^n)^2+2(3x^n)(4)+4^2$ This is in the same form as the formula above where $a=3x^n$ and $b=4$. Use the formula above to have: $=(3x^n+4)^2$
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