Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set: 104

Answer

$(x^n+9)(x^n-2)$

Work Step by Step

The given expression can be written as: $\\(x^n)^2+7x^n-18$ The constant term of $-18$ has the factors 9 and $-2$, the sum of which, 7, is equal to the coefficient of the middle term. Thus, the factored form of the given trinomial is: $\\=(x^n+9)(x^n-2)$
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