## Intermediate Algebra (6th Edition)

$(x^n+9)(x^n-2)$
The given expression can be written as: $\\(x^n)^2+7x^n-18$ The constant term of $-18$ has the factors 9 and $-2$, the sum of which, 7, is equal to the coefficient of the middle term. Thus, the factored form of the given trinomial is: $\\=(x^n+9)(x^n-2)$