## Intermediate Algebra (6th Edition)

$(2x^n-3)^2$
RECALL: $a^2-2ab+b^2=(a-b)^2$ The given trinomial can be written as: $\\=(2x^n)^2-2(2x^n)(3)+3^2$ This is in the same form as the formula above where $a=2x^n$ and $b=3$. Use the formula above to have: $\\=(2x^n-3)^2$