Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 304: 109

Answer

$x^2(x+5)(x+1) $

Work Step by Step

Factoring the $GCF= x^2 ,$ the given expression, $ x^4+6x^3+5x^2 ,$ is equivalent to \begin{array}{l}\require{cancel} x^2(x^2+6x+5) .\end{array} Using the FOIL Method which is given by $(a+b)(c+d)=ac+ad+bc+bd,$ the expression above is equivalent to \begin{array}{l}\require{cancel} x^2(x+5)(x+1) .\end{array} Let \begin{array}{l}\require{cancel}Y_1= x^4+6x^3+5x^2 \text{ and }\\Y_2= x^2(x+5)(x+1) .\end{array} Using a graphing calculator, the graph of $Y_1$ (dotted red graph) and $Y_2$ (solid blue graph) are given below. Since the two graphs coincide, then $Y_2$ and $Y_1$ are the same. That is, $Y_2$ is the correct factored form of $Y_1.$
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