Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 304: 94

Answer

$y^3+1$

Work Step by Step

Using $ (a\pm b)(a^2\mp ab+b^2)=a^3\pm b^3 $, then, \begin{align*} (y+1)(y^2-y+1) \Rightarrow y(y^2)+(1)(1) \\= y^3+1 .\end{align*}
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