Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 304: 101



Work Step by Step

The given expression can be written as: $\\(x^n)^2+10x^n+16$ The constant term of 16 has the factors 8 and 2, the sum of which, 10, is equal to the coefficient of the middle term Thus, the factored form of the given trinomial is: $\\=(x^n+8)(x^n+2)$
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