## Intermediate Algebra (6th Edition)

$(x^n+8)(x^n+2)$
The given expression can be written as: $\\(x^n)^2+10x^n+16$ The constant term of 16 has the factors 8 and 2, the sum of which, 10, is equal to the coefficient of the middle term Thus, the factored form of the given trinomial is: $\\=(x^n+8)(x^n+2)$