## Intermediate Algebra (6th Edition)

$(x^n-4)(x^n-3)$
The given expression can be written as: $\\(x^n)^2-7x^n+12$ The constant term of 12 has the factors $-4$ and $-3$, the sum of which, -7, is equal to the coefficient of the middle term. Thus, the factored form of the given trinomial is: $\\=(x^n-4)(x^n-3)$