Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set: 102

Answer

$(x^n-4)(x^n-3)$

Work Step by Step

The given expression can be written as: $\\(x^n)^2-7x^n+12$ The constant term of 12 has the factors $-4$ and $-3$, the sum of which, -7, is equal to the coefficient of the middle term. Thus, the factored form of the given trinomial is: $\\=(x^n-4)(x^n-3)$
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