Answer
$\sqrt[3]{x}\cdot\sqrt[3]{x}=\sqrt[3]{x^2}$
Work Step by Step
Using $\sqrt[n]{a}\cdot\sqrt[n]{b}=\sqrt[n]{ab}$, the expression $
\sqrt[3]{x}\cdot\sqrt[3]{x}
$ is equivalent to
\begin{align*}
&
\sqrt[3]{x\cdot x}
\\&=
\sqrt[3]{x^2}
.\end{align*}
Hence, $\sqrt[3]{x}\cdot\sqrt[3]{x}$ is equal to $\sqrt[3]{x^2}$ and not equal to $x$.
