Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises - Page 459: 49

Answer

$-4\sqrt 2$

Work Step by Step

$-\sqrt 32=-\sqrt (16\times2)=-\sqrt 16\times\sqrt 2=-4\sqrt 2$ We know that $\sqrt 16=4$, because $4^{2}=16$.
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