Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises - Page 459: 56

Answer

$2\sqrt[3] 3$

Work Step by Step

$\sqrt[3] 24=\sqrt[3] (8\times3)=\sqrt[3] 8\times\sqrt[3] 3=2\sqrt[3] 3$ We know that $\sqrt[3] 8=2$, because $2^{3}=8$.
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