Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises - Page 459: 65


$-3\sqrt[5] 2$

Work Step by Step

$-\sqrt[5] 486=-\sqrt[5] (243\times2)=-\sqrt[5] 243\times\sqrt[5] 2=-3\sqrt[5] 2$ We know that $\sqrt[5] 243=3$, because $3^{5}=243$.
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