## Intermediate Algebra (12th Edition)

Using the properties of radicals, the expression, $\sqrt{48}$, is equivalent to \begin{align*} & \sqrt{16\cdot3} \\&= \sqrt{16}\cdot\sqrt{3} &(\text{use }\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}) \\&= 4\sqrt{3} .\end{align*} With $\sqrt{48}$ equivalent to $4\sqrt{3}$, then $\sqrt{48}$ can be simplified. Hence, Choice B.