## Intermediate Algebra (12th Edition)

$\frac{\sqrt k}{10}$
According to the quotient product of radicals, $\sqrt[n] \frac{a}{b}=\frac{\sqrt[n] a}{\sqrt[n] b}$ (where $\sqrt[n] a$ and $\sqrt[n] b$ are real numbers and $n$ is a natural number). That is, the nth root of a quotient is the quotient of the nth roots. Therefore, $\sqrt \frac{k}{100}=\frac{\sqrt k}{\sqrt 100}=\frac{\sqrt k}{10}$. $\sqrt 100=10$, because $10^{2}=100$