Answer
$2\sqrt[5] 4$
Work Step by Step
$\sqrt[5] 128=\sqrt[5] (32\times4)=\sqrt[5] 32\times\sqrt[5] 4=2\sqrt[5] 4$
We know that $\sqrt[5] 32=2$, because $2^{5}=32$.
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises - Page 459: 64
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