Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.1 - Radical Expressions and Graphs - 7.1 Exercises - Page 440: 69

Answer

$x^{5}$

Work Step by Step

We know that $\sqrt[3] x^{15}=x^{5}$, because $(x^{5})^{3}=x^{5\times3}=x^{15}$.
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