Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.1 - Radical Expressions and Graphs - 7.1 Exercises - Page 440: 50

Answer

Graph of $ f(x)=\sqrt[3]{x}+1 $

Work Step by Step

Substituting values of $x$ in the given function, $ f(x)=\sqrt[3]{x}+1 $, results to \begin{array}{l|r} \text{If }x=-1: & \text{If }x=0 \\\\ f(x)=y=\sqrt[3]{x}+1 & f(x)=y=\sqrt[3]{x}+1 \\ y=\sqrt[3]{-1}+1 & y=\sqrt[3]{0}+1 \\ y=-1+1 & y=0+1 \\ y=0 & y=1 \end{array} \begin{array}{l|r} \text{If }x=1: & \text{If }x=8 \\\\ f(x)=y=\sqrt[3]{x}+1 & f(x)=y=\sqrt[3]{x}+1 \\ y=\sqrt[3]{1}+1 & y=\sqrt[3]{8}+1 \\ y=1+1 & y=2+1 \\ y=2 & y=3 .\end{array} Connecting the points $ \left(-1,0\right), \left(0,1\right), \left(1,2\right), \text{ and } \left(8,3\right) $ with a curve gives the graph of $ f(x)=\sqrt[3]{x}+1 $.
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