Answer
Graph of $
f(x)=\sqrt[3]{x+1}
$
Work Step by Step
Substituting values of $x$ in the given function, $
f(x)=\sqrt[3]{x+1}
$, results to
\begin{array}{l|c|r}
\text{If }x=-9: & \text{If }x=-2 & \text{If }x=-1
\\\\
f(x)=y=\sqrt[3]{x+1} &
f(x)=y=\sqrt[3]{x+1} &
f(x)=y=\sqrt[3]{x+1}
\\
y=\sqrt[3]{-9+1} &
y=\sqrt[3]{-2+1} &
y=\sqrt[3]{-1+1}
\\
y=\sqrt[3]{-8} &
y=\sqrt[3]{-1} &
y=\sqrt[3]{0}
\\
y=-2 &
y=-1 &
y=0
\end{array}
\begin{array}{l|r}
\text{If }x=0: & \text{If }x=7
\\\\
f(x)=y=\sqrt[3]{x+1} &
f(x)=y=\sqrt[3]{x+1}
\\
y=\sqrt[3]{0+1} &
y=\sqrt[3]{7+1}
\\
y=\sqrt[3]{1} &
y=\sqrt[3]{8}
\\
y=1 &
y=2
.\end{array}
Connecting the points $
\left(-9,-2\right),
\left(-2,-1\right),
\left(-1,0\right),
\left(0,1\right),
\text{ and }
\left(7,2\right)
$ with a curve gives the graph of $
f(x)=\sqrt[3]{x+1}
$.
