#### Answer

not a real number

#### Work Step by Step

We know that $\sqrt[8] -1$ is not a real number, because there is no number $a$ such that $a^{8}=-1$.
In general, the nth root of a, written as $\sqrt[n] a$, will not be a real number if $a$ (also known as the radicand) is negative and $n$ (also known as the index) is positive.