Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.1 - Radical Expressions and Graphs - 7.1 Exercises - Page 440: 31



Work Step by Step

We know that $\sqrt \frac{64}{81}=\frac{8}{9}$, because $(\frac{8}{9})^{2}=\frac{8}{9}\times\frac{8}{9}=\frac{8\times8}{9\times9}=\frac{64}{81}$.
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