Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.1 - Radical Expressions and Graphs - 7.1 Exercises - Page 440: 33



Work Step by Step

We know that $\sqrt[3] \frac{64}{27}=\frac{4}{3}$, because $(\frac{4}{3})^{3}=\frac{4}{3}\times\frac{4}{3}\times\frac{4}{3}=\frac{4\times4\times4}{3\times3\times3}=\frac{64}{27}$.
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