Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.1 - Radical Expressions and Graphs - 7.1 Exercises - Page 440: 32



Work Step by Step

We know that $\sqrt \frac{100}{9}=\frac{10}{3}$, because $(\frac{10}{3})^{2}=\frac{10}{3}\times\frac{10}{3}=\frac{10\times10}{3\times3}=\frac{100}{9}$.
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