Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.1 - Radical Expressions and Graphs - 7.1 Exercises - Page 440: 46

Answer

Graph of $ f(x)=\sqrt{x-5} $

Work Step by Step

Substituting values of $x$ in the given function, $ f(x)=\sqrt{x-5} $, results to \begin{array}{l|r} \text{If }x=5: & \text{If }x=6 \\\\ f(x)=y=\sqrt{x-5} & f(x)=y=\sqrt{x-5} \\ y=\sqrt{5-5} & y=\sqrt{6-5} \\ y=\sqrt{0} & y=\sqrt{1} \\ y=0 & y=1 \end{array} \begin{array}{l|r} \text{If }x=9 & \text{If }x=14 \\\\ f(x)=y=\sqrt{x-5} & f(x)=y=\sqrt{x-5} \\ y=\sqrt{9-5} & y=\sqrt{14-5} \\ y=\sqrt{4} & y=\sqrt{9} \\ y=2 & y=3 .\end{array} Connecting the points $ \left(5,0\right), \left(6,1\right), \left(9,2\right), \text{ and } \left(14,3\right) $ with a curve gives the graph of $ f(x)=\sqrt{x-5} $.
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