## Intermediate Algebra (12th Edition)

$2y+3=0$
Using $y-y_1=m(x-x_1)$ or the point-slope form of linear equations, the equation of the line passing through $\left( -\dfrac{3}{4},-\dfrac{3}{2} \right)$ and with a slope of $m= 0$ is \begin{array}{l}\require{cancel} y-\left( -\dfrac{3}{2} \right)=0 \left(x-\left( -\dfrac{3}{4} \right) \right) \\\\ y+\dfrac{3}{2}=0 \left(x+\dfrac{3}{4} \right) \\\\ y+\dfrac{3}{2}=0 \\\\ 2y+3=0 .\end{array}