Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.3 - Writing Equations of Lines - 2.3 Exercises: 51

Answer

$x+2y=8$

Work Step by Step

Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the two-point form of linear equations, the equation of the line passing through $( 6,1 )$ and $( -2,5 )$ is \begin{array}{l}\require{cancel} y-1=\dfrac{1-5}{6-(-2)}(x-6) \\\\ y-1=\dfrac{1-5}{6+2}(x-6) \\\\ y-1=\dfrac{-4}{8}(x-6) \\\\ y-1=-\dfrac{1}{2}(x-6) \\\\ 2(y-1)=-1(x-6) \\\\ 2y-2=-x+6 \\\\ x+2y=6+2 \\\\ x+2y=8 .\end{array}
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