Answer
$y=2$
Work Step by Step
Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the two-point form of linear equations, the equation of the line passing through $(
-2,2
)$ and $(
4,2
)$ is
\begin{array}{l}\require{cancel}
y-2=\dfrac{2-2}{-2-4}(x-(-2))
\\\\
y-2=\dfrac{2-2}{-2-4}(x+2)
\\\\
y-2=\dfrac{0}{-6}(x+2)
\\\\
y-2=0
\\\\
y=2
.\end{array}