Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.3 - Writing Equations of Lines - 2.3 Exercises: 29

Answer

$y=-\frac{3}{5}x+3$

Work Step by Step

A line in slope-intercept form has the equation: $y=mx+b$ ($m=slope$, $b=y-intercept$) We see from the table that the point $(0,3)$ corresponds to the $y$-intercept. Thus $b=3$. To calculate the slope between points $(x_1,y_1)$ and $(x_2,y_2)$, we use the formula: $slope=m=\frac{y_2-y_1}{x_2-x_1}$ We plug in the points $(0,3)$ and $(5,0)$: $slope=m=\frac{0-3}{5-0}=\frac{-3}{5}$ Thus the equation must be: $y=-\frac{3}{5}x+3$
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