#### Answer

$5x+y=-10$

#### Work Step by Step

Using $y-y_1=m(x-x_1)$ or the point-slope form of linear equations, the equation of the line passing through $(
-2,0
)$ and with a slope of $m=
-5
$ is
\begin{array}{l}\require{cancel}
y-0=-5(x-(-2))
\\\\
y=-5(x+2)
.\end{array}
In the form $y=mx+b$, the equation above is equivalent to
\begin{array}{l}\require{cancel}
y=-5(x+2)
\\\\
y=-5x-10
.\end{array}
In the form $Ax+By=C$, the equation above is equivalent to
\begin{array}{l}\require{cancel}
y=-5x-10
\\\\
5x+y=-10
.\end{array}
Hence, the different forms of the equation of the line with the given conditions are
\begin{array}{l}\require{cancel}
\text{slope-intercept form: }
y=-5x-10
\\\\
\text{standard form: }
5x+y=-10
.\end{array}