Intermediate Algebra (12th Edition)

(a) $y=\frac{7}{3}x-1$ (b) $slope=m=\frac{7}{3}$ (c) $y-intercept=b=-1$; point $(0,-1)$ (d) See graph.
(a) A line in slope-intercept form has the equation: $y=mx+b$ ($m=slope$, $b=y-intercept$) We put the equation into slope-intercept form: $7x-3y=3$ $-3y=3-7x$ $-3y=-7x+3$ $y=\frac{7}{3}x-1$ (b) We see that $slope=m=\frac{7}{3}$ (c) We see that $y-intercept=b=-1$; point $(0,-1)$ (d) See graph.