## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$x=\left\{ -\dfrac{3}{10},\dfrac{3}{10} \right\}$
Dividing both sides by $100,$ the given expression is equivalent to \begin{array}{l}\require{cancel} 100x^2=9 \\\\ x^2=\dfrac{9}{100} .\end{array} Taking the square root of both sides (Square Root Property), the solutions are \begin{array}{l}\require{cancel} x=\pm\sqrt{\dfrac{9}{100}} \\\\ x=\pm\sqrt{\left(\dfrac{3}{10}\right)^2} \\\\ x=\pm\dfrac{3}{10} .\end{array} Hence, the solutions are $x=\left\{ -\dfrac{3}{10},\dfrac{3}{10} \right\} .$