Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.5 Polynomials and Factoring - R.5 Exercise Set - Page 970: 28



Work Step by Step

Factoring the negative $GCF=-3,$ the given expression is equivalent to \begin{array}{l}\require{cancel} -3y^2-12y-12 \\\\= -3(y^2+4y+4) .\end{array} Using the factoring of trinomials in the form $x^2+bx+c,$ the $\text{ expression }$ \begin{array}{l}\require{cancel} -3(y^2+4y+4) \end{array} has $c= 4 $ and $b= 4 .$ The two numbers with a product of $c$ and a sum of $b$ are $\left\{ 2,2 \right\}.$ Using these two numbers, the $\text{ expression }$ above is equivalent to \begin{array}{l}\require{cancel} -3(y+2)(y+2) \\\\= -3(y+2)^2 .\end{array}
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