Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.5 Polynomials and Factoring - R.5 Exercise Set - Page 970: 34


$x=\left\{ -1,3,\dfrac{9}{2} \right\}$

Work Step by Step

Equating each factor to zero (Zero Product Property), then \begin{array}{l}\require{cancel} x-3=0 \\\\\text{OR}\\\\ x+1=0 \\\\\text{OR}\\\\ 2x-9=0 .\end{array} Solving each equation results to \begin{array}{l}\require{cancel} x-3=0 \\\\ x=3 \\\\\text{OR}\\\\ x+1=0 \\\\ x=-1 \\\\\text{OR}\\\\ 2x-9=0 \\\\ 2x=9 \\\\ x=\dfrac{9}{2} .\end{array} Hence, the solutions are $ x=\left\{ -1,3,\dfrac{9}{2} \right\} .$
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