Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.5 Polynomials and Factoring - R.5 Exercise Set - Page 970: 35

Answer

$x=\pm3$

Work Step by Step

Taking the square root of both sides (Square Root Property), the solutions to the given equation are \begin{array}{l}\require{cancel} x^2=9 \\\\ x=\pm\sqrt{9} \\\\ x=\pm3 .\end{array}
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