## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(t-2)(t^2-5)$
Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} t^3-2t^2-5t+10 \\\\= (t^3-2t^2)-(5t-10) .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} (t^3-2t^2)-(5t-10) \\\\= t^2(t-2)-5(t-2) .\end{array} Factoring the $GCF= (t-2)$ of the entire expression above results to \begin{array}{l}\require{cancel} (t-2)(t^2-5) .\end{array}