Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.5 Polynomials and Factoring - R.5 Exercise Set: 3

Answer

$(y-3)^2$

Work Step by Step

Using the factoring of trinomials in the form $x^2+bx+c,$ the given expression, $ y^2-6y+9 ,$ has $c$ equal to $ 9 $ and $b$ equal to $ -6 .$ The two numbers that give a product of $c$ and a sum of $b$ are $\{ -3,-3 \}.$ Hence, the factored form of the expression above is \begin{array}{l}\require{cancel} (y-3)(y-3) \\\\= (y-3)^2 .\end{array}
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