## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(y-11)^2$
The expression above is equivalent to \begin{array}{l}\require{cancel} y^2+121-22y \\\\= y^2-22y+121 .\end{array} Using the factoring of trinomials in the form $x^2+bx+c,$ the $\text{ expression }$ \begin{array}{l}\require{cancel} y^2-22y+121 \end{array} has $c= 121$ and $b= -22 .$ The two numbers with a product of $c$ and a sum of $b$ are $\left\{ -11,-11 \right\}.$ Using these two numbers, the $\text{ expression }$ above is equivalent to \begin{array}{l}\require{cancel} (y-11)(y-11) \\\\= (y-11)^2 .\end{array}