Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.5 Polynomials and Factoring - R.5 Exercise Set: 29

Answer

$(y-11)^2$

Work Step by Step

The expression above is equivalent to \begin{array}{l}\require{cancel} y^2+121-22y \\\\= y^2-22y+121 .\end{array} Using the factoring of trinomials in the form $x^2+bx+c,$ the $\text{ expression }$ \begin{array}{l}\require{cancel} y^2-22y+121 \end{array} has $c= 121 $ and $b= -22 .$ The two numbers with a product of $c$ and a sum of $b$ are $\left\{ -11,-11 \right\}.$ Using these two numbers, the $\text{ expression }$ above is equivalent to \begin{array}{l}\require{cancel} (y-11)(y-11) \\\\= (y-11)^2 .\end{array}
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